Happy Easter.
Granted, a Bayesian might hold that rationality places no constraint on probabilistic judgments beyond coherence (or conformity to the probability calculus). Then as long as the strict atheist assigns probability 1 to God's non-existence alongside his or her assignment of 0 to God's existence, no norm of rationality has been violated.
Furthermore, an assignment of p = 0 would clearly block the route to Pascal's conclusion. For then the expectation calculations become:
E(wager for God) = ∞*0 + f1*(1 − 0) = f1E(wager against God) = f2*0 + f3*(1 − 0) = f3
And nothing in the argument implies that f1 > f3. (Indeed, this inequality is questionable, as even Pascal seems to allow.) In short, Pascal's wager has no pull on strict atheists.
4 comments:
true, indeed. no pull.
but have you got an equation?
nope, so I must be an aeqationist too.
Wales has a proud history in equations that your comment led me to explore. See today's post.
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